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2w^2-14w=-12
We move all terms to the left:
2w^2-14w-(-12)=0
We add all the numbers together, and all the variables
2w^2-14w+12=0
a = 2; b = -14; c = +12;
Δ = b2-4ac
Δ = -142-4·2·12
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-10}{2*2}=\frac{4}{4} =1 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+10}{2*2}=\frac{24}{4} =6 $
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